(1/2x)-1=(1/3)(^2x-1)

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Solution for (1/2x)-1=(1/3)(^2x-1) equation: 



(1/2x)-1=(1/3)(^2x-1)

We move all terms to the left:

(1/2x)-1-((1/3)(^2x-1))=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)(^2x-1))!=0

x∈R



We add all the numbers together, and all the variables

(+1/2x)-((+1/3)(^2x-1))-1=0

We get rid of parentheses

1/2x-((+1/3)(^2x-1))-1=0

We calculate fractions


3x/6x^2+(-((+1*2x)/6x^2-1=0

We calculate fractions

We do not support expression: x^4

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